This is a true or false problem on a homework assignment of mine. I am inclined to believe it is true, but I don't know how to prove it, and I can't come up with a counterexample to prove it false. Can anyone help?Need help! True or false: The only functions with fourth derivative y^(4)=sinx must be of the form y=sinx + c?
Function
y(x) = sin(x) + x
is also goodNeed help! True or false: The only functions with fourth derivative y^(4)=sinx must be of the form y=sinx + c?
TRUE
The derivative of the sin function is the cos function.
The derivative of the cos function is the sin function.
So any odd numbered derivative of a sin or cos function will be the opposite, for example:
y = sin x
dy/dx = cos x
d3y/dx3 = cos x
d5y/dx5 = cos x
etc.
Conversely any even numbered derivative of a sin or cos function will be the same function, for example:
y = cos x
dy/dx = sin x
d2y/dx2 = cos x
d4y/dx4 = cos x
When working in reverse (i.e. when integrating), you must always add on the unknown constant C that is lost in the differentiation operation.
Edit: ooops, forgot that dy/dx (cos x) = -sin x
Nevertheless, the answer is still true.
Begin with f''''(x) = sin(x) and now integrate four times.
f'''(x) = cos(x) + h
f''(x) = -sin(x) + hx + k
f'(x) = -cos(x) + (h/2)x^2 + kx + u
f(x) = sin(x) + (h/6)x^3 + (k/2)x^2 + ux + v.
Any equation of this form will have a fourth derivative = sin(x). h, k, u, and v are constants, of course.
y^4
4y^3
12y^2
24y
take the derivative four times, this number is like the sinx bit and the +C is the constant which isn't accounted for in the derivative.
i think that's right!
hope it helped!
True
f(x) = sinx
f ' (x) = cos x
f '' (x) = -sin x
f ''' (x) = -cos x
f ';'; (x) = sin x
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